Y=ax² + bx + c and A(-2,18), B(0.4), C(4,24) given
1)Let's determine 1st the value of c in using the pair of B
4= a(0)² + b(0) + c , c=4 and y=ax²+bx+4
2) Use the pair of A: 18 = 4a -2b + 4===> 4a-2b=14
3) Use C pair: 24 = 16a+4b+4 ==> 16a+4b=20
4) solve the system equation in 2) and 3) and you'll find a=2 and b=-3
Hence the equation is y =2x²-3x+4
Answer:
Step-by-step explanation:
we see that y = -3x-3
substitute that into the other equation to get
-3x-3 = 2x+7
-5x = 10
x = -2
so, y = -3(-2)-3 = 3
check to make sure (-2,3) solves both equations.
Answer:

Step-by-step explanation:
<u>Logarithms</u>
Some properties of logarithms will be useful to solve this problem:
1. 
2. 
3. 
We are given the equation:

Applying the second property:

Substituting:

Applying the first property:

Operating:

Rearranging:

Simplifying:

Dividing by 3:

Applying the third property:

Applying inverse logs:

Answer:
x=45
Step-by-step explanation:
add (3x-9)+30+24=180
subtract 30 and 24 from both sides
(3x-9) = 126
+9 on both sides
3x=135
divide by 3 on both sides
x=45
Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c =
= 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !