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stepladder [879]
3 years ago
7

The line ab has midpoint (-2,4). a has coordinates (3,-2). find the coordinates of b

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0

Answer:

B = (-7,10)

Step-by-step explanation:

Given that , a line AB has midpoint (-2,4) and the coordinates of A is ( 3 , -2). We need to find out the coordinates of B .

  • Let coordinate of B be ( p,q ). We can use midpoint formula , as ,

=> Midpoint = ( x₁ + x₂ / 2 , y₁ + y₂/2 )

=> ( -2,4 ) = ( p + 3)/2 , ( q -2 )/2

  • On comparing ,

=> -2 = p + 3/2

=> p + 3 = -4

=> p = -3 - 4

=> p = (-7)

<u>Also </u><u>:</u><u>-</u><u> </u>

=> q - 2/2 = 4

=> q -2 = 8

=> q = 8 + 2

=> q = 10

<h3><u>Hence</u><u> the</u><u> </u><u>coordinates</u><u> </u><u>of </u><u>B </u><u>is</u><u> </u><u>(</u><u> </u><u>-</u><u>7</u><u>,</u><u>1</u><u>0</u><u> </u><u>)</u><u> </u><u>.</u></h3>
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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
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Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

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substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

5 0
3 years ago
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