Answer:
one point (on origin),
Step-by-step explanation:
graph of Y=X^2 is parabolic ,and x intecept means the point where ,Y COORDINATE (ORDINATE) becomes 0
so now after putting y=0 in eqution we got
x^2=0
i.e, x=0
that means at (0,0) ,so only one point!
✌️:)
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:
70,000-50,000=20,000
Step-by-step explanation:
Answer:
you just have to check the first and the third box
Step-by-step explanation:
put each into slop intercept form
y+6=-5(x-2) is the same as y=-5x+4
y-2=-5(x+6) is the same as y=-5x-28
y=-5x+4
y=-5x-28
all of them have a slope of -5, but you need to plug in (2,-6) to see which on is true