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3 years ago

I need help please!

Mathematics

1 answer:

wlad13 [49]3 years ago

5 0

Answer:

Tell me you address right now!!!

Step-by-step explanation:

I am gonna call police for help!

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What is the value of X?

d1i1m1o1n [39]

Answer:

x=10

Step-by-step explanation:

We can use the angle bisector theorem to solve this problem

8 12

-------- = ---------

x+4 2x+1

Using cross products

8(2x+1) = 12(x+4)

Distribute

16x+8 = 12x+48

Subtract 12x from each side

16x -12x +8 = 12x-12x +48

4x +8 = 48

Subtract 8 from each side

4x+8-8 = 48-8

4x = 40

4x/4 = 40/4

x=10

3 0

3 years ago

Which of the following square roots would not be between 4 and 5?

expeople1 [14]

Answer:

√10.

___________________

7 0

2 years ago

Read 2 more answers

SHOW WORK PLEASE!!!!!!!!!!!!!!!!!

MakcuM [25]

Answer:

Step-by-step explanation:

add hen sub ten bom anwwer

8 0

2 years ago

Somebody can help me plz? It seems easy for y’all but not for me haha

Naddika [18.5K]

Answer:

I'll say 25 but not too sure!

3 0

3 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$