On interval 0 ≤ x < 2π, where are the x-intercepts of y = cos(2x)?
2 answers:
You might be interested in
Answer:
(A) f(x) = 2 *
Step-by-step explanation:
[] We can find our answer by plugging the x values into the functions as t and solving.
-. Using this method, starting with the A function, we find that the first function models the data and we do not need to test the others. I still have shown the work for the others as it is good to check your work.
[✓] f(x) = 2 *
(1, 8) }{}{}{ f(x) = 2 * = 2 * 4 = 8
(2, 32) }{}{}{ f(x) = 2 * = 2 * 16 = 32
(3, 128) }{}{}{ f(x) = 2 * = 2 * 64 = 128
-> This pattern continues
[✗] f(x) =
(1, 8) }{}{}{ f(x) = = 4 ≠ 8
-> This function does not model the data as it does not fulfil the first point
[✗] f(x) = 4 *
(1, 8) }{}{}{ f(x) = 4 * = 4 * 2 = 8
(2, 32) }{}{}{ f(x) = 4 * = 4 * 4 = 16 ≠ 32
-> This function only models (1, 8) but does not fully model the data
[✗] f(x) =
(1, 8) }{}{}{ f(x) = = 8
(2, 32) }{}{}{ f(x) = = 64 ≠ 32
-> This function only models (1, 8) but does not fully model the data
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
$3900.
Step-by-step explanation:
If retirement is taken at the age of 67 years, income = $1300 per month.
% Loss, if retirement taken at the age of 62 years = 25% per month
Loss in dollars per month if retirement taken at the age of 62 years = 25% of Monthly income if retirement is taken at the age of 67 years
We know that there are 12 months in an year.
So, annual loss in total annual income over one year:
Loss in dollars per month 12 :
325 12 = <em>3900$</em>