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morpeh [17]
3 years ago
7

This graph represents which function?

Mathematics
1 answer:
il63 [147K]3 years ago
4 0

Answer:

A

Step-by-step explanation:⁻7+

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Can someone help me with this
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

6. 78-2(3+16) /4

(78-2x19)/4

( 78 -38)/4

40/4=10

7.

(66/11)3 -6*8

6x6x6 -48

216-48=168

8.

10/7+2(8-11/2)

10/7+2(8-5.5)

10/7+2*2.5

10/7+5

10/7 + 35/7

45/7 =

5 0
3 years ago
The measure of an angle is 32°. what is the measure of its complementary angle??​
valkas [14]

Answer:

58

Step-by-step explanation:

because sum of complementary angles is 90°

4 0
3 years ago
Find the appropriate perimeter of the figure below
yanalaym [24]

Answer:

55.7 in.

Step-by-step explanation:

I assume the figure is a rectangle and a half circle.

The three sides of the rectangle that need to be added toward the perimeter measure 15 in., 10 in., and 15 in.

Then you need the circumference of the half circle which has a 10-inch diameter.

circumference = (pi)d

circumference = 3.14 * 10 in. = 31.4 in.

We only need half the circumference, so we have 31.4 in./2 = 15.7 in.

Now we add the three sides of the rectangle listed above and the circumference of the half circle.

perimeter = 15 in. + 10 in. + 15 in. + 15.7 in.

perimeter = 55.7 in.

8 0
3 years ago
Read 2 more answers
Convert from rectangular to polar coordinates: note: choose rr and θθ such that rr is nonnegative and 0≤θ<2π0≤θ<2π (a)(9,0
DochEvi [55]

Answer:

Step-by-step explanation:

Convert rectangle (x , y) to polar coordinates ( r , θ)

x=r  \cos \theta, y= r \sin \theta

r=\sqrt{x^2+y^2} , \theta =tan^-^1 (\frac{y}{x} )

a) converts (9, 0) to polar coordinates  ( r , θ)

r=\sqrt{x^2+y^2} \\\\=\sqrt{9^2+0} \\\\=9

\theta= \tan^-^1 (\frac{0}{9} )\\\\=0

b) Convert (18,\frac{18}{\sqrt{3} } ) to polar coordinates ( r, θ)

r = \sqrt{18^2+(\frac{18}{\sqrt{3} })^2 } \\\\=\sqrt{324+108} \\\\=\sqrt{432}

\frac{x}{y} \theta = \tan^-^1(\frac{\frac{18}{\sqrt{3} } }{18} )\\\\= \tan ^-^1(\frac{1}{\sqrt{3} } )\\\\= \frac{\pi}{6}

c)  converts (-5, 5) to polar coordinates  ( r , θ)

r =\sqrt{(-5)^2+(5)^2} \\\\=\sqrt{50} \\\\=5\sqrt{2}

\theta=\tan^-^1(\frac{5}{-5} )\\\\= \tan^-^1(-1)\\\\=\frac{3\pi}{4}

d)  converts (-1, √3) to polar coordinates  ( r , θ)

r=\sqrt{(-1)^2+(\sqrt{3})^2 } \\\\= \sqrt{4} \\\\=2

\theta=\tan^-^1(\frac{\sqrt{3} }{-1} )\\\=\tan^-^1(-\sqrt{3} )\\\\=\frac{2\pi}{3}

= \frac{2\pi}{\sqrt{3} }

6 0
3 years ago
NERDS HELP ME !!!!!!!!
Ivahew [28]

Answer:

63 it's the closest

Step-by-step explanation:

5 0
3 years ago
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