Filling in the given values in point-slope equation
y = m(x -x₁) +y1
you have
y = 1(x -5) +3
This simplifies to ...
A. y = x - 2
Answer:
t = 2.52 seconds
Step-by-step explanation:
h=139-15t-16t^2
We want to know when the ball hits the ground
That would be when h=0
0 = 139-15t-16t^2
We can use the quadratic formula to find t
t = -b ± sqrt(b^2-4ac)
----------------------
2a
where a = -16 b = -15 and c = 139
t = -(-15) ± sqrt((-15)^2-4(-16)139)
----------------------
2(-16)
t = (15) ± sqrt(225+8896)
----------------------
-32
t = (15) ± sqrt(9121)
----------------------
-32
t = 15+ sqrt(9121) t = 15- sqrt(9121)
-------------------- or -------------------
-32 -32
-3.453247707 or 2.515747707
Since time cannot be negative
2.515747707
Round to the nearest hundredth
t = 2.52 seconds
Answer:
138
Step-by-step explanation:
Answer:
s = 4·3^t
Step-by-step explanation:
After the first term, each term in the sequence is 3 times the previous one. This is a description of a geometric sequence. Here, the first term is 4, so the general term is ...
an = 4·3^n . . . . for n counting from 0
We can name the function "s" for "speed" and use "t" for the time in seconds. Then the equation is ...
s = 4·3^t
