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aalyn [17]
2 years ago
9

Find the value of root 7 upto 6 decimal​​

Mathematics
1 answer:
Nuetrik [128]2 years ago
7 0

Answer:

root 7 = 2.645751( rounded up to 6 d.p)

Mark as brainlest, follow and thank

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Round to the nearest tenth
Vitek1552 [10]

<em>Note: I am assuming we have to determine the angle 'Ф'.</em>

Answer:

The value of Ф = 22.6°

Step-by-step explanation:

Given

hypotenuse = 13

To determine:

Angle = Ф = ?

Using the trigonometric ratio

cos Ф = adjacent / hypotenuse

here

  • hypotenuse = 13
  • Adjacent to Ф = 12

so substituting adjacent = 12, hypotenuse = 13 in the equation

cos Ф = adjacent / hypotenuse

cos Ф = 12 / 13

Ф = arccos (12/13)

Ф = 22.6°

Therefore, the value of Ф = 22.6°

8 0
3 years ago
Find the area of the triangle below.<br> Be sure to include the correct unit in your answer.
musickatia [10]

Answer:

1050

Step-by-step explanation:

Multiply all 3 numbers

20x7=140 140x15=2100

Then divide by 2

2100/2=1050

Hope this helps :)

7 0
3 years ago
Simplify -8/2 divided by 6/-3
Bogdan [553]
I think the answer is 3, -8/2  /    6/-3 .... then you flip and multiply to get to -8/2 x -3/6 which = 24/8 which is equal to 3
3 0
4 years ago
Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
How do you find the x intercept and coordinates of the vertexfor the parabola y=x^2-14x+49????
lbvjy [14]
y=x^2-14x+49=\underbrace{x^2-2x\cdot7+7^2}_{use\ (a-b)^2=a^2-2ab+b^2}=(x-7)^2\\\\Vertex\ form\ of\ a\ quadratic\ function:\\\\y=a(x-h)^2+k\ where\ coordinates\ of\ the\ vertex\ (h;\ k)\\\\\boxed{vertex:(7;\ 0)}\\\\x-intercept\ (y=0):\\\\(x-7)^2=0\iff x-7=0\Rightarrow \boxed{x=7}\\\\\\Answer:\\\\x-intercept:(7;\ 0)\\\\the\ coordinates\ of\ the\ vertex:(7;\ 0)

7 0
4 years ago
Read 2 more answers
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