Answer: A
Step-by-step explanation:
15 packages damaged. Cost is -175.50 this is a loss. So 15x(-175.50)
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
Yes, I am 99% sure your right.
85 = 10x+15
70 = 10x
x = 7
180-85 = 95 = z
Answer:
0.004
Step-by-step explanation:
4 x 1
4
<-- move decimal 3 to the left
0.004
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