All categories

3 years ago

A shipping company damaged 15 packages. Each package was valued at $175.50. Which expression represents this situation?

Mathematics

1 answer:

Allushta [10]3 years ago

3 0

Answer: A

Step-by-step explanation:

15 packages damaged. Cost is -175.50 this is a loss. So 15x(-175.50)

You might be interested in

Sheila purchased ski equipment for $513 using a six-month deferred payment plan. The interest rate after the introductory period

klemol [59]

$65 * 6 = $390 total monthly payments made

The downpayment made is $125, so the total balance at the end is:

balance = $513 – ($125 + $390)

balance = - $2

<span>There is an excess of 2 dollars at the end.</span>

4 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

Chase has 3 gallons of a solution that is 30% antifeeze that he wants to use to winterize his car. How much pure antifreeze shou

makvit [3.9K]

Let x gallons be the amount of pure antifreeze that should be added to the 30% solution to produce a solution that is 65% antifreeze. Then the total amount of antifreeze solution will be x+3 gallons.

There are 30% of pure antifreeze in 3 gallons of solution, then

3 gallons - 100%,

a gallons - 30%,

where a gallons is the amount of pure antifreeze in given solution.

Mathematically,

$\dfrac{3}{a}=\dfrac{100}{30},\\ \\a=\dfrac{3\cdot 30}{100}=0.9\ gallons.$

Now in new solution there will be x+0.9 gallons of pure antefreeze.

x+3 gallons - 100%,

x+0.9 - 65%

$\dfrac{x+3}{x+0.9}=\dfrac{100}{65},\\ \\65(x+3)=100(x+0.9),\\ \\65x+195=100x+90,\\ \\35x=105,\\ \\x=3\ gallons.$

Answer: he should add 3 gallons of pure antifreeze.

8 0

3 years ago

Whats the bisector of the photosentisis of the yellow sun???!??!??!

LenKa [72]

Answer:

you will use dy DX for the equation of photosynthesis. make carbon subject of formular, and factorize the final answer

7 0

2 years ago

student expanded an expression, as shown. Is the student's work correct? Explain why or why not. −6 ( 4x − 2 13 ) −6(4x) + 6 ( −

sleet_krkn [62]

Answer:

No, the student's work is not correct.

Step-by-step explanation:

Given : Student expanded an expression, as shown.

$-6(4x-\frac{2}{13} )$

$-6(4x)+6(-\frac{2}{13} )$

$-24x-\frac{12}{13}$

To find : Is the student's work correct?

Solution :

The expansion of student is not correct.

Follow the below steps to get correct solution and student mistake,

Step 1 - Write the expression,

$-6(4x-\frac{2}{13} )$

Step 2 - Apply distributive property, $a(b+c)=ab+ac$

$=(-6)(4x)+(-6)(-\frac{2}{13})$

Step 3 - Solve,

$=-24x+\frac{12}{13}$

The student was mistaken in step 2 in solving the sign.

4 0

3 years ago

Read 2 more answers