Your answer is: 20

They have 4 different backgrounds and 5 different poses which means you just have to multiply the 4 backgrounds*the 5 different poses to discover how many different pictures you could have at the most.

hope this helps!

4 0

3 years ago

7. The points P(2, -3), Q(3, -2) and R(8, z) are

Hatshy [7]

Answer:

z = 3

Step-by-step explanation:

Since the points are collinear then the slopes between the points are equal.

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = P (2, - 3) and (x₂, y₂ ) = Q (3, - 2)

m = $\frac{-2+3}{3-2}$ = 1

Repeat with

(x₁, y₁ ) = Q (3, - 2) and (x₂, y₂ ) = R (8, z )

m = $\frac{z+2}{8-3}$ = $\frac{z+2}{5}$ , then

$\frac{z+2}{5}$ = 1 ( multiply both sides by 5 )

z + 2 = 5 ( subtract 2 from both sides )

z = 3

4 0

3 years ago