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lawyer [7]
3 years ago
7

What is the equation of the circle with a radius of 4 and a center at (3, 2) ?

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0

Answer:

(x - 3)^2 + (y + 2)^2 = 16

Step-by-step explanation:

(x - h)^2 + (y - k)^2 = r^2

r = radius

(h, k ) is center of circle.

The center of the circle is (3, 2) and r is 4.

(x - 3)^2 + (y + 2)^2

16

Best of luck :3

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What is 5/8 with a denominator of 24?
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Step-by-step explanation:

you multiply 8*3 to get 24 so you do the same to 5. so 5*3 = 15 so 15/24

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If the minute hand of a clock moves 45 degrees, how many minutes of time have passed?​
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45 minutes have passed

Step-by-step explanation:

1 degree = 1 minute

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Write down the ratio of the total number of medals won by Russia to the total number of medals won by Germany.
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S is the centroid of triangle XYZ. What is the length of SW? 5 units 11 units 22 units 28 units plzzz help
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8 0
3 years ago
Read 2 more answers
The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per
ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that \mu = 2

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

We want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707

P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804

P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902

P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176

1.76% probability that in one hour more than 5 clients arrive

8 0
3 years ago
Read 2 more answers
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