Question

What is the equation of the circle with a radius of 4 and a center at (3, 2) ?

Answer 1

Answer:

(x - 3)^2 + (y + 2)^2 = 16

Step-by-step explanation:

(x - h)^2 + (y - k)^2 = r^2

r = radius

(h, k ) is center of circle.

The center of the circle is (3, 2) and r is 4.

(x - 3)^2 + (y + 2)^2

16

Best of luck :3