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3 years ago

Which of the following statements are true?

Mathematics

2 answers:

Kobotan [32]3 years ago

8 0

Answer:I believe the answer is D

Step-by-step explanation:

Y_Kistochka [10]3 years ago

7 0

Answer:

I believe the answer is D, all the proportional relationships are functions.

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X Cube - 5x Square - 2 x + 24

Otrada [13]

Answer:

(x+2)(x-4)(x-3)

(x²-4x+2x-2)(x-3)

(x²-2x-2)(x-3)

=x³-5x²-2x+24

So the answer true

8 0

3 years ago

ANSWER THIS HURRYYYYYY

gladu [14]

Answer:

I believe its B, sorry if im wrong

Step-by-step explanation:

7 0

2 years ago

Could I get help on some algebra? I need the explanation to know how to do it. +45 points

Fiesta28 [93]

Answer:

Step-by-step explanation:

A is right, D is right because they are on the outside and on different sides, B is actually right since they are on the inside and on different sides, so that leaves c, so this has to be the wrong one because they are not both interior since 5 is on the outside and 6 is inside even if they are both on the same side

6 0

3 years ago

Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f

GalinKa [24]

Answer:

$\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }$

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

$\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}$

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

$f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240$

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in $\mathbb{R}$ .

$\\f(x)=(x^2+16)(x^2-2x-15)$

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

$f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}$

And we can write in $\mathbb{C}$

$f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0

3 years ago

HELP ASAPPPPP<br> When graphing the inequality y > -4x + 6, what type of line should be graphed?

melomori [17]

Answer:

A dashed line

Step-by-step explanation:

The end points of the line for the inequality would not be included since y is only greater, not greater than or equal to.

6 0

3 years ago