Answer:
see attached
Step-by-step explanation:
GeoGebra conveniently computes the point coordinates of the reflected points. In the attached, the reflections are done in the order listed in the table, so A' is reflected across x; A'₁ is reflected across y; A'₂ is reflected across y=x, and A'₃ is reflected across y=-x. The same notation is used for the other points. The values are listed in order, so you can copy them down the column in your table.
Subtract 4 from 1480 to get 1476. Divide that by 12 to get 123 . The quotient is 113 with the remainder of 4
Answer:
3x - 6
Step-by-step explanation:
To determine the equation that would be perpendicular with a certain line, we must first know the characteristics of a perpendicular line. This line would have a 90 degrees angle with another line so that the slope of this line would be the negative reciprocal of the slope of the other line. To write the equation, given a certain point we use the point-slope form of a line, y -y1 = m(x - x1).
Original line: <span>-x + 5y= 14
y = x/5 + 14/5
slope = 1/5
Perpendicular line's slope = -5
y - y1 = m (x - x1)
</span> y - (-2) = -5 (x - (-5))
y = -5x - 25 -2
y = -5x -27