Answer:
180
Step-by-step explanation:
A=1/2*b*h
A= 1/2*8*25
180
Answer:
24: x = 31
25: x = 15
Step-by-step explanation:
Remark
24 is supplementary which means that the two angles add to 180o which is on the right hand side of the equation
25 is complementary which means that the two angles add to 90o which is on the left hand side of the equation
Twenty Four
3x + 31 +2x - 6 = 180 Collect the like terms
3x +2x + 31 - 6 = 180 Do the adding and subtracting.
5x + 25 = 180 Subtract 25 from both sides
5x + 25 - 25 = 180 - 25
5x = 155 Divide by 5
x = 155/5
x = 31
Check
3x + 31 = 3*31 + 31
3x + 31 = 93 + 31
3x + 31 = 124
2x - 6 = 2*31 - 6 = 62 - 6 = 56
Total 124 + 56 = 180 as it should.
Twenty Five
Equation
3x+ 4x - 15 = 90
Solution
7x - 15 = 90 Like terms have been collected on the left.
7x = 90 + 15 15 was added to both sides
7x = 105 Divide by 7
x = 15 I'll leave the check to you
Answer:
C
Step-by-step explanation:
The relationship is y = 3x
Answer:
See Below.
Step-by-step explanation:
We want to verify the equation:

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

Simplify. The denominator uses the difference of two squares pattern:

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

Split into two separate fractions:

Rewrite the two fractions:

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

Hence verified.
This is just combining like terms.....
6n2 - 5n2 + 7n2
n2 + 7n2
=8n2