Answer: The outbound trip is 18 miles per hour
Step-by-step explanation:
Let x represent the speed of the plane.
An aircraft carrier made a trip. Let us assume that this trip was outbound. The trip there took 5 hours.
Distance = speed × time. Therefore
Distance = 5x
The trip back took 6 hours. It averaged 3 mph faster on the trip there then on the return trip. This means that the speed on the trip back is x - 3 mph.
Distance = 6(x-3) = 6x - 18
Since the distance is the same,
5x = 6x - 18
6x - 5x = 18
x = 18
The speed on return or inbound trip would be 18 - 3 = 15 mph
The correct answer is B⬅
(The student incorrectly reflected across the x-axis)......✔
Answer:
answers are B,C and E
you got it right YAYYY !!!
good job haha
Step-by-step explanation:
9(5)-4(-7)-15
45+28-15
73-15
58
TO determine the mass of the helium in the balloon, we make use of the density of the gas that is given in the problem and the volume of helium that is present. <span>Density is a property of a
material which describes the mass of a material per unit volume. By multiplying the volume to density, we get the mass of the helium gas in the balloon. We do as follows:
Mass = Density x Volume
Mass = 0.1785 kg / m^3 x 3249 m^3
Mass = 579.9465 kg
Therefore, the mass of helium gas in the hot air balloon would be about 579.9 kg.</span>