Answer:
Option (B) is the correct answer to the following question.
Explanation:
Here, in the code "const" is the constant keyword which is used when we need that the value stored in that variable will never change.
The following option is correct because the assignment operator are those operator which initialize the value in the variable and overloading of the assignment operator would be as we use the other operators and also we could use them by creating the objects as we use in the copy constructor.
So, that's why the following option is correct.
Answer:
BX will hold 6444 in hex format.
Explanation:
From the given information:
We need to understand that AX is 64-bit hex number.
When performing ASM instruction (Assembly language instruction),
The addition of 2111 + 4333 = 6444 will be in BX.
This is because ADD, BX, AX will add bx and ax; and the final outcome will be stored in BX.
∴
BX will hold 6444 in hex format.
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1. A compatible OS
2. A fast processor
3. Storage space
4. Memory modules