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Xelga [282]
3 years ago
11

Please answer this as soon as possible.

Mathematics
1 answer:
OleMash [197]3 years ago
7 0

Answer:1st one is acute 2nd one is also acute 3rd one is obtuse last one is right

Step-by-step explanation:

Because I learned this already

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Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
$3.00 is ____ % of $1.80
natta225 [31]
1.666666666666667%

3.00/1.80


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4 years ago
With the values in the same order but with parentheses make the following sentence true
LenKa [72]

Answer:

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Step-by-step explanation:

It is more easier like that

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lara [203]
No, she did not substitute the correct x and y values :)
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(-3)-(+2)-(-4)+(1)+(-2)-(-3) =
tankabanditka [31]

Answer:

1

Step-by-step explanation:

-3-2= -6

4+1=5

-2+3=1

-5+5+1=1

8 0
3 years ago
Read 2 more answers
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