Question

For question 4 pls help me , show work step by step

Answer 1

Answer:

c=6.40 units

$\implies \angle B=32\degree$

Step-by-step explanation:

The given triangle ABC is a right triangle;

According to the Pythagoras Theorem;

$c^2=|AC|^2+|BC|^2$

We substitute AC=5 and BC=8

$c^2=5^2+8^2$

$c^2=25+16$

$c^2=41$

$c=\sqrt{41}$

c=6.40 to two decimal places.

In a right triangle the two acute angles add up to 90 degrees.

$\angle B+58\degree=90\degree$

$\implies \angle B=90\degree-58\degree$

$\implies \angle B=32\degree$