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3 years ago

How do we solve the following: 49=495;593;59305

Mathematics

1 answer:

amid [387]3 years ago

5 0

Answer:

...

Step-by-step explanation:

You should probably change your semicolons first. Maybe you should type this more clearly ^^

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2x + 3y = -6 -2x + 3y = 6 How do I graph it

Elanso [62]

Answer:

$(-3, 0)$

Step-by-step explanation:

$\: \: \: 2x + 3y = - 6 \\ -2x + 3y = \: \: \: 6 \\ \frac{ + \: \: \: \: \: \: - \: \: \: \: \: \: = - }{ }{} \\ \: \: \: 4x \: \: \: \: \: \: \: \: \: \: \: \: = - 12 \\ \\ x = \frac{ - 12}{4} \\ \\ x = - 3$

now,

$-2( - 3) + 3y = 6 \\ 6 + 3y = 6 \\ 3y = 6 - 6 \\ 3y = 0 \\ y = \frac{0}{ 3} \\ y = 0$

thus, (-3, 0)

3 0

3 years ago

Which of the following can be probality of an event. 0.4, 1.3, 0.8 ,0?

kondaur [170]

I would thinks it’s 1.7

7 0

3 years ago

Percent of change 125 is increased to 200

Montano1993 [528]

Answer:

Step-by-Step Explanation:

(200-125):125*100 =

(200:125-1)*100 =

160-100 = 60

Now we have: What is the percentage increase/decrease from 125 to 200 = 60

6 0

3 years ago

Read 2 more answers

To compare two products such as colas, a random sample is selected to taste two types of colas (A and B). Each selected subject

Nadya [2.5K]

Answer: The sample size would be needed = 385

Step-by-step explanation:

Let p be the prior population proportion.

Margin of error = E

When not estimate of p is given , the formula to calculate the minimum sample size n = $0.25(\dfrac{z^*}{E})^2$ , where z* = critical value for given confidence interval.

Here z* for 95% confidence level is 1.96.

E=5%=0.05

Then $n=0.25(\dfrac{1.96}{0.05})^2\approx385$

Hence, the sample size would be needed = 385

8 0

3 years ago

Suppose you by a 1.25 pound package of ham at $5.20 per pound

marishachu [46]

I suppose I can do that and end up spending 6.50$?

1.25 x 5.20 = 6.50 final amount due.

6 0

3 years ago