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kirill115 [55]
3 years ago
6

ABCD~EFGH. identify the pairs of congruent angles and the corresponding sides.

Mathematics
1 answer:
Finger [1]3 years ago
7 0

Answer:

We need a picture p-p

Step-by-step explanation:

You might be interested in
Which of the following is equivalent to the complex number -8(7i - 3i^2)
Leni [432]

Answer:  B) -56i - 24

This is the same as -24 - 56i

=============================================

Explanation:

The 'i' refers to the imaginary number \sqrt{-1}

In other words, i = \sqrt{-1}

Squaring both sides gets us i^2 = -1

So,

x = -8(7i - 3i^2)\\\\x = -8(7i - 3(-1))\\\\x = -8(7i + 3)\\\\x = -8(7i) -8(3)\\\\x = -56i -24 \ \ \text{ .... Answer: Choice B}\\\\x = -24 - 56i\\\\

The result is in the form a+bi where a = -24 is the real part and b = -56 is the imaginary part.

7 0
3 years ago
PLEASE HELP                                                                                                                    
sweet [91]
To model and solve our situation we are going to use the equation: s= \frac{d}{t}
where
s is speed
d is distance 
t is time 

1. We know that the distance between the cities is 2400 miles, so d=2400. We also know that the speed of the plane is 450 mi/h. Since we don't know the speed of the air, S_{a}=?. We don't know how much the westward trip takes, so t_{w}=?, and we also don't know how much the eastward trip takes, so t_{e}=?.

Going westward. Here the plane is flying against the air, so we need to subtract the speed of the air from the speed of the plane:
450-S_{a}= \frac{2400}{t_{w} }
Going eastward. Here the plane is flying with the the air, so we need to add the speed of the air to the speed of the plane:
450+S_{a}= \frac{2400}{t_{e} }

2. We know for our problem that the round trip takes 11 hours; so the total time of the trip is 11, t_{t}=11. Notice that we also know that the total time of the trip equals time of the tip going westward plus time of the trip going eastward, so t_{t}=t_{w}+t_{e}. Since we know that the total trip takes 11 hours, we can replace that value in our total time equation and solve for t_{w}:
11=t_{w}+t_{e}
t_{w}=11-t_{e}

Now we can replace t_{w} in our going westward equation to model our round trip with a system of equations:
450-S_{a}= \frac{2400}{t_{w}}
450-S_{a}= \frac{2400}{11-t_{e} } equation (1)
450+S_{a}= \frac{2400}{t_{e}} equation (2)

3. To solve our system of equations, we are going to solve for t_{e} in equations (1) (2):

From equation (1)
450-S_{a}= \frac{2400}{11-t_{e} }
11-t_{e}= \frac{2400}{450-S_{a} }
-t_{e}= \frac{2400}{450-S_{a} } -11
t_{e}=11- \frac{2400}{450-S_{a} }
t_{e}= \frac{4950-11S_{a} -2400}{450-S_{a} }
t_{e}= \frac{2550-11S_{a} }{450-S_{a} } equation (3)

From equation (2):
450+S_{a}= \frac{2400}{t_{e} }
t_{e}= \frac{2400}{450+S_{a} } equation (4)

Replacing (4) in (3)
\frac{2400}{450+S_{a}} = \frac{2550-11S_{a}}{450-S_{a} }
Now, we can solve for S_{a} to find the speed of the wind:
2400(450-S_{a})=(450+S_{a})(2550-11S_{a})
1080000-2400S_{a}=1147500-4950S_{a}+2550S_{a}-11(S_{a})^{2}
11(S_{a})^{2}-67500=0
11(S_{a})^{2}=67500
(S_{a})^{2}= \frac{67500}{11}
S_{a}=+/-  \sqrt{ \frac{67500}{11} }
Since speed cannot be negative, the solution of our equation is:
S_{a}= \sqrt{ \frac{67500}{11} }
S_{a}=78.33

We can conclude that the speed of the wind is 78 mph.

3 0
4 years ago
What are the steps and properties to this problem
lawyer [7]
3(2m+12) -4m = 20 -3(3m+5)

Step 1. Distribute 3 to (2m+12) and -3 to (3m+5)

Distribution property:
When you are distributing, you multiply the outside number by the numbers inside. For example,
-1(4-2)
-1 times 4, -1 times -2
-4, 2 (negative times negative =positive)
Then you would get
-4+2. You do not distribute with multiplication and division. So then we would do this with our numbers.

6m+36 -4m = 20 -9m-15
______
Step 2. Simplify by adding like terms.

Like terms:
Terms are separated by operation symbols (+,-,*,➗). Like terms are terms with the same variable next to it. 5a and 6a are like terms. Terms with no variables at all are also like terms. 5 and 6 are like terms. 8a and 7 are not like terms. 9a and 9b are not like terms.

6m+-4m= 2m. 20+(-15)=5
_____
2m+36=5-9m

Step 3. Add 9m to both sides
11m+36=5
____
Step 4. Subtract 36 from both sides
11m=-31
____
Step 5. Divide by 11
m=-31/11





If you can please provide brainliest. I took 30 minutes doing this.

3 0
3 years ago
Translate the equation
weeeeeb [17]

Answer:

C.) Three times the sum of twice a number and one  is equal to twelve more than the product of three  and a number.

Step-by-step explanation:

i hope this helps

3 0
3 years ago
Read 2 more answers
The equation d = 3t gives the distance, d, in meters that Liam swims with respect to time, t, in seconds.
Natasha_Volkova [10]

Answer:

Liam's rate = 3 meters per second

Edgar's rate = 3.2 meters per second

Edgar swims faster

Step-by-step explanation:

<u>Liam:</u>

The equation d=3t gives the distance, d, in meters that Liam swims with respect to time, t, in seconds.

When t=0,\ d=0.

When t=1,\ d=3.

Rate of change:

\dfrac{3-0}{1-0}=3

Liam's rate is 3 metres per second.

<u>Edgar:</u>

When t=20, \ d=64.

When t=40,\ t=128.

Rate of change:

\dfrac{128-64}{40-20}=\dfrac{64}{20}=3.2

Edgar's rate is 3.2 metres per second.

Edgar swims faster.

5 0
3 years ago
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