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Phoenix [80]
3 years ago
13

What is ─7g + 5 = 2 – g – 7g solved to the variable???

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Answer:

g = -3

Step-by-step explanation:

-7g + 5 = 2 – g – 7g

Combine like terms

-7g + 5 = 2 -8g

5 = 2 + -g

3 = -g

-3 = g

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2(m + 1) = 16 <br> full answer
Serhud [2]

Answer:

2m+2=16, then do the isolate m but doing the inverse operation of 2 which is now -2 and add that to 16 would be left with 2m=14 and 14/2 is 7 so m=7

Step-by-step explanation:

3 0
3 years ago
IXL!! I WILL ADD BRAINLIST!
klio [65]

Answer:

-3,3.1, 3 2/10

Step-by-step explanation:

When you are putting different numbers from least to greatest, you need to put them in the same form...

First things first we should put -3 wayy up front. negative numbers are worth less than positive numbers.

Then we need to turn 3 2/10 into a decimal.

3 2/10 -------> 3.2

3.2 is more than 3.1

Thus, the order is

-3,3.1, 3 2/10

Hope this helps and have a nice day.

8 0
3 years ago
Read 2 more answers
HELP!
pashok25 [27]
Multiplying both sides of    <span>−1/3x≤−6    by -3 results in "x is equal to or greater than 18."
 
Note that multiplying such an inequality requires reversing the direction of the inequality symbol.

I subst. 18 for x in   </span><span>−1/3x≤−6    as a check, and found that  the resulting inequality is true.</span>
7 0
4 years ago
Read 2 more answers
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
Plz help me answer this!!!
Rasek [7]

Answer: 88 years

Step-by-step explanation:

4 0
3 years ago
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