Answer:
min at (3, 0 )
Step-by-step explanation:
given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
= - 
y = (x - 3)² = x² - 6x + 9 ← in standard form
with a = 1 and b = - 6 , then
= - 
= 3
substitute x = 3 into the equation for corresponding value of y
y = (3 - 3)² = 0² = 0
vertex = (3, 0 )
• if a > 0 then vertex is minimum
• if a < 0 then vertex is maximum
here a = 1 > 0 then (3, 0 ) is a minimum
Answer:
<em>( About ) 1.77 seconds; Option B</em>
Step-by-step explanation:
We are given the equation h ( t ) = - 16t^2 + 50, so in order to determine the time let us determine the x - intercept for y ⇒ 0;
- 16t^2 + 50 = 0,
- 16t^2 = - 50,
t^2 = 25 / 8,
Thus t ⇒ √ ( 25 / 8 ), and t ⇒ - √ ( 25 / 8 ),
t ⇒ ( 5√2 )/ 4, and - ( 5√2 )/ 4,
But time is represented only by a positive value, thus
t ⇒ ( 5√2 )/ 4 = 1.767766953......., ( About ) 1.77 seconds
<em>Answer; ( About ) 1.77 seconds; Option B</em>
Four lbs of granola = 13 lbs
Six lbs of raisins = 12 lbs
13+12=25
25/$2.50=10
6 is yo answer cuz
ANSWER^^
