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Nadusha1986 [10]
3 years ago
10

Make a the subject of a2+b2=c2

Mathematics
1 answer:
wel3 years ago
4 0

Answer:

a=\sqrt{c^2-b^2

⇒ a=\sqrt{(c+b)(c-b)}        [Factorized form]

Step-by-step explanation:

Given expression:

a^2+b^2=c^2

We need to make a the subject.

In order to do that we need to solve the expression for a in terms of b and c

We have,

a^2+b^2=c^2

Subtracting both sides by b^2

a^2+b^2-b^2=c^2-b^2

a^2=c^2-b^2

Taking square root both sides in order to remove square of a

\sqrt{a^2}=\sqrt{c^2-b^2}

a=\sqrt{c^2-b^2

The difference of squares can be factorized and written  as:

a=\sqrt{(c+b)(c-b)}    [difference of squares x^2-y^2=(x+y)(x-y) ]

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Possibly meters or feet/yards.

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Answer:

Option A. 65 trees

Step-by-step explanation:

From the question given:

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2 years ago
PLEASE HELP The areas of two similar triangles are 50 dm2, and 32 dm2. The sum of their perimeters is 117 dm. What is the perime
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Answer:

65 dm and 52 dm

Step-by-step explanation:

If the scale factor of the sides is k, then the scale factor of the areas is k^2.

The scale factor of the areas is (32 dm^2)/(50 dm^2) = 0.64 = k^2

The scale factor of the sides is k = \sqrt(0.64) = 0.8

The perimeters are in a ratio of 1:0.8

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