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Nadusha1986 [10]
2 years ago
10

Make a the subject of a2+b2=c2

Mathematics
1 answer:
wel2 years ago
4 0

Answer:

a=\sqrt{c^2-b^2

⇒ a=\sqrt{(c+b)(c-b)}        [Factorized form]

Step-by-step explanation:

Given expression:

a^2+b^2=c^2

We need to make a the subject.

In order to do that we need to solve the expression for a in terms of b and c

We have,

a^2+b^2=c^2

Subtracting both sides by b^2

a^2+b^2-b^2=c^2-b^2

a^2=c^2-b^2

Taking square root both sides in order to remove square of a

\sqrt{a^2}=\sqrt{c^2-b^2}

a=\sqrt{c^2-b^2

The difference of squares can be factorized and written  as:

a=\sqrt{(c+b)(c-b)}    [difference of squares x^2-y^2=(x+y)(x-y) ]

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Explanation:

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6 0
3 years ago
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Find sin (A-B) if sin A = 4/5 with A between 90 and 180 and if cos B = 3/5 with B between 0 and 90
quester [9]

Answer:

sin(A-B) = 24/25

Step-by-step explanation:

The trig identity for the differnce of angles tells you ...

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We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.

And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.

Then ...

sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25

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Answer:

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