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Y_Kistochka [10]
3 years ago
5

Find the area 2 m 4 m 10 m

Mathematics
1 answer:
mina [271]3 years ago
6 0

Answer:

30.285 m²

Step-by-step explanation:

C = 2πr

2 · π · 2

≈ 12.57

12.57 ÷ 2 = 6.285

10 - 2 = 8

8 · 4 ÷ 2

32 ÷ 2

16

2 · 4 = 8

6.285 + 8 + 16

30.285

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Solve for a<br><br> 3a+2&gt; 3a-6/3
RUDIKE [14]

Answer:

a>-2

Step-by-step explanation:

4 0
3 years ago
Nima uses 2/3 cup peanuts, 1/2 cup cashews, 3/4 cups pecans, and some raisinsin a recipe that makes 2 1/4 cups of trail mix. How
Lesechka [4]

Answer:

8/27 cups

Step-by-step explanation:

Nima uses 2/3 cups of peanuts to make a recipe of 2 1/4 = 9/4 cups of trail mix. If we want to find how many cups of peanuts are there per cup of trail mix, we can do a rule of three:

If 9/4 cups of trail mix need 2/3 cups of peanuts, 1 cup of trail mix need X cups of peanuts:

9/4 cups of trail mix -> 2/3 cups of peanuts

1 cup of trail mix -> X cups of peanuts

9/4 / 1 = 2/3 / X

9/4 = 2/(3*X)

3*X*9 = 4*2

27*X = 8

X = 8/27 cups

7 0
3 years ago
If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI
Vikentia [17]

Answer:

The value is      y  =  \$ 225

Step-by-step explanation:

From the question we are told that

   The amount charge per year is  k  =  \$ 200

   The  number of members it will have at this amount is  n  =  50

   The amount amount increase that will lead to the loss of a single member is   z =  \$ 5

        Generally the total amount the club would obtain from  its members is mathematically represented as

      I  =  Amount \  due\ paid *  Number \  of members

Now let x denote the number of member lost

Hence

      I  =  (k + zx) (n-x )

=>    I  =  (200 + 5x) (50-x )

=>  I  = 10000+50x-5x^2

Thus the number of members that be removed to  give the maximum  income from dues is obtained by differentiating the above equation and equating it to zero

           \frac{dI}{dx}  =  50-10x

=>         x   =  5

So from  I  =  (200 + 5x) (50-x ) we have

          I  =  (200 + 5 (5)) (50-5 )

           I  = \$ 10125

So the amount the club should charge is    

         y  =  \frac{10125}{50 - 5}

         y  =  \$ 225

         

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