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avanturin [10]
4 years ago
8

The radius of a single atom of a generic element x is 197 picometers (pm and a crystal of x has a unit cell that is face-centere

d cubic. calculate the volume of the unit cell.
Chemistry
1 answer:
Vinvika [58]4 years ago
7 0
In a face centered cubic unit cell, the volume occupied by the particles of the substance is about 74% of the total unit cell. First, we find the volume of a single atom assuming it to be sphere:
Volume(atom) = 4/3 x π x r³
Volume(atom) = 4/3 x π x (197 x 10⁻¹²)³
Volume(atom) = 2.87 x 10⁻²⁹ m³

There are a total of 4 atoms in a FCC unit cell, so the total volume occupied by atoms is:
2.87 x 10⁻²⁹ x 4
= 1.15 x 10⁻²⁸ m³

Volume of cell = (1.15 x 10⁻²⁸ ) / 0.74
Volume of cell = 1.55 x 10⁻²⁸ m³
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polet [3.4K]
I remember coming across this question and the options were:
KOH, HCN, NH₃, HI, Sr(OH)₂

Now, a substance with a low pH is one that dissociates completely in water to release hydrogen ions, while basic substances dissociate completely to release hydroxide ions. Therefore, in the order of increasing pH:
HI, HCN, NH₃, Sr(OH)₂, KOH
7 0
3 years ago
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
Why will liquids evaporate even at room temperature?
mr Goodwill [35]
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6 0
3 years ago
Complete combustion of 3.20g of a hydrocarbon produced 9.69g of CO2 and 4.96g of H2O. What is the empirical formula for the hydr
vlabodo [156]

Let empirical formula for hydrocarbon is CxHy

it will undergo combustion as

CxHy + (x + y/4) O2  ---> xCO2 + (y/2 )H2O

Given that mass of CO2 produced = 9.69 g

So moles of CO2 produced = 9.69 / 44 = 0.22 moles

So moles of carbon present = 0.22 moles

mass of H2O produced = 4.96 g

Moles of H2O produced = mass / molar mass = 4.96 / 18 = 0.28 moles

So moles of H present = 2 X 0.28 = 0.56 moles

Let us divided the moles of each with lowest value of moles

Moles of Carbon = 0.22 / 0.22 = 1 moles

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the ratio of carbon and hydrogen will be : C:H = 2:5

empirical formula : C2H5


4 0
3 years ago
Read 2 more answers
When the equation below is correctly balanced, the coefficient for CO2 is
vaieri [72.5K]

Answer:

The answer to your question is 4

Explanation:

Chemical reaction

                C₂H₆  +  O₂  ⇒  CO₂  +  H₂O

           Reactants    Elements    Products

                  2            Carbon              1

                  6            Hydrogen         2

                  2            Oxygen             3

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒  4CO₂  +  6H₂O

           Reactants    Elements    Products

                  4            Carbon             4

                 12            Hydrogen       12

                 14            Oxygen           14

When the reaction is balanced the coefficient for CO₂ is 4.

5 0
3 years ago
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