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3 years ago

11

What is the "major drawback" to using word equations?

2 answers:

Ber [7]3 years ago

5 0

C) Word equations are not quantitative.

Anettt [7]3 years ago

3 0

Answer:

C

Explanation:

they can be put in other languages

they are literally the name of the chemical

they don't show quantity

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Need help with 22 and 24<br>

choli [55]

Answer:

22:

Formular:

$atomic \: mass = \frac{ \sum(isotopic \: mass \times \%abundance)}{100} \\$

substitute:

$atomic \: mass = \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100} \\ \\ = \frac{(1887.620) + (253.108) + (290.230)}{100} \\ \\ = \frac{2430.958}{100} \\ \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}$

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: <u>Atoms</u><u> </u><u>with</u><u> </u><u>same</u><u> </u><u>proton</u><u> </u><u>number</u><u> </u><u>but</u><u> </u><u>different</u><u> </u><u>mass</u><u> </u><u>number</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>isotopes</u>

5 0

3 years ago

Read 2 more answers

Word equation of nitrogen + oxygen —--> ammonia

katrin [286]

Answer:

it is ammonia nitro oxide

5 0

2 years ago

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Horizontal<br> rows are called

klio [65]

In math it’s just horizontal in science it’s periods

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3 years ago

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why are experimental investigations the best type of scientific investigation to demonstrate cause and effect relationships

Lelu [443]

Because they are coming from the ground and always safe

8 0

3 years ago

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At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppo

RoseWind [281]

Answer:

$[SO_3]=0.25M$

Explanation:

Hello there!

In this case, since the integrated rate law for a second-order reaction is:

$[SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}$

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

$[SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\$

$[SO_3]=0.25M$

Best regards!

4 0

2 years ago