Answer:
The area is 200.96 in^2
Step-by-step explanation:
Answer:
theres no clock
Step-by-step explanation:
Answer:
It can hold up to
of waste
<em></em>
Step-by-step explanation:
Given
-- Diameter
-- height
Required
Determine the amount of waste it can hold
This simply means that we calculate the volume of the cylindrical container.
And this is calculated using:
![Volume = \pi r^2h](https://tex.z-dn.net/?f=Volume%20%3D%20%5Cpi%20r%5E2h)
Where
![\pi = 3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D%203.14)
and
![r = \frac{D}{2}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7BD%7D%7B2%7D)
![r = \frac{1.5}{2}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B1.5%7D%7B2%7D)
![r = 0.75](https://tex.z-dn.net/?f=r%20%3D%200.75)
So, we have:
![Volume = 3.14 * 0.5^2 * 1.6](https://tex.z-dn.net/?f=Volume%20%3D%203.14%20%2A%200.5%5E2%20%2A%201.6)
![Volume = 1.256ft^3](https://tex.z-dn.net/?f=Volume%20%3D%201.256ft%5E3)
<em>Hence, it can hold up to </em>
<em> of waste</em>
2x+4 is the length of one side