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scZoUnD [109]
3 years ago
13

What is 24=78^2 what is it

Mathematics
1 answer:
PolarNik [594]3 years ago
7 0

Answer:

24  =  6084

Step-by-step explanation:

24 is already simpflied. So 78 times 78 is left.

Which is easy and equals to 6084.

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Which of the following is the minimum value of the equation y= 1/3 x^2+2x+5?
kirill115 [55]
THE CORRECT ANSWER IS C)-3
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3 years ago
Hi there. I am having an issue figuring out which is the base and which is the length.
Paha777 [63]

We can split the given figure in 2 right triangles:

So, in order to get the area of each triangle, we need to find the base, denoted by x in both of them. Since both are right triangles, we can to apply Pythagoresn theorem. By applying this theorem to right hand side triangle, we have

x^2+8^2=17^2

so we have

\begin{gathered} x^2+64=289 \\ then \\ x^2=289-64 \\ x^2=225 \end{gathered}

Then, x is given by

x=\sqrt{225}=15

Then, the area of the left triangle is given by

A_1=\frac{base\times height}{2}=\frac{15\times36}{2}=270in^2

Similarly, the area of the second triangle is given by

A_2=\frac{base\times height}{2}=\frac{15\times8}{2}=60in^2

Then, the area of the entire figure is the sum of the area of the 2 triangles, that is,

A=A_1+A_2=270+60=330in^2

Therefore, the answer is: 330 square inches

8 0
1 year ago
What fraction is £1 of 13p?
Rasek [7]
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4 0
3 years ago
What is m∠BEC ?<br><br><br> Enter your answer in the box.
Stels [109]
We are able to set 4x+32 equal to 6x-8 because these are congruent vertical angles

4x+32=6x-8
4x+40=6x (add 8 to both sides)
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X=20 (divide both sides by 2)

Then we plug in 20 for x into 6x-8 to find the answer

6(20)-8
=120-8
=112

Hope this helps!
8 0
3 years ago
Read 2 more answers
F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0
3 years ago
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