Answer:
C, D and E
Step-by-step explanation:
Assuming
f(x) = √(9−8x)
and the options are:
A. p(x) = √(-8x) and q(x)=9+x
B. p(x) = √(9+x) and q(x)=8x
C. p(x) = √(-x) and q(x)=8x−9
D. p(x)=√(9−x) and q(x)=8x
E. p(x)=√x and q(x)=9−8x
F. p(x)=9−8x and q(x)=√x
G. All of the above
H. None of the above
Substituting in f(x)=p(q(x)) we get:
A. √(-8(9+x)) = √(-72 - 8x)
B. √(9+(8x)) = √(9+8x)
C. √(-(8x−9
)) = √(-8x + 9)
D. √(9−(8x)) = √(9−8x)
E. √(9−8x
)
F. 9−8(√x
) = 9 - 8√x
The awnser would be c or 54 in that case
Answer:
The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.
The function to represent the mass of the sample after t days is 
Step-by-step explanation:
Exponential equation of decay:
The exponential equation for the amount of a substance is given by:

In which A(0) is the initial amount and r is the decay rate, as a decimal.
Hourly rate of change:
Decreases 26% by day. A day has 24 hours. This means that
; We use this to find r.



![\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}](https://tex.z-dn.net/?f=%5Csqrt%5B24%5D%7B%281-r%29%5E%7B24%7D%7D%20%3D%20%5Csqrt%5B24%5D%7B0.74%7D)



The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.
Starts out with 810 grams of Element X
This means that 
Element X is a radioactive isotope such that its mass decreases by 26% every day.
This means that we use, for this equation, r = 0.26.
The equation is:



The function to represent the mass of the sample after t days is 
The answer to this equation is :-10x+38 because
-2x(x-3)+4(-2x+8)
(-2x+6)+(-8x+32)
(-2x+6)(-8x+32)
-2x+6-8x+32
-10x+38
You would be able to cut 144 pieces of wire from the spool because 270/1 7/8 (or 1.875) equals 144