An easy way to solve fraction problems like this is to make each fraction have the same denominator. Since he has $100, the denominator will be 100.
2/10=?/100 10*10=100 1*10=20 20/100 of his money he wants to spend on video games
55/100 already has 100 as its denominator, so he wants to spend 55/100 on a skateboard.
3/10=?/100 10*10=100 3*10=100 30/100 is how much he wants to spend on comic books.
Add all of the fractions together to see how much he wants to spend and if he has enough.
20/100+55/100+30/100=105/100
He wants to spend $105, which is $5 more than he has.
Answer:
<em>Zeina had 35 books and Ali had 5 books</em>
Step-by-step explanation:
<u>Equations</u>
We know Zeina has seven times as many books as Ali. If we call
x = Number of books Ali has
Then Zeina has
7x = Number of books Zeina has
We also know if Zeina gave Ali 15 books, they would have the same number of books, thus:
x + 15 = 7x - 15
Adding 15:
x + 15 +15 = 7x
Subtracting x:
15 +15 = 7x - x
Operating:
30 = 6x
Dividing by 6:
x = 30 / 6
x =5
7x = 35
Thus Zeina had 35 books and Ali had 5 books
