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Maksim231197 [3]
3 years ago
5

A rectangular tank has a base that is 10 centimeters by 5 centimeters and a height of 20 centimeters. If the tank is half full o

f water, by how many centimeters will the water level rise if 325 cubic centimeters are poured into the tank?
Mathematics
1 answer:
Serga [27]3 years ago
6 0

the answer will be 6.5 cm the water will rise

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T
chubhunter [2.5K]

9514 1404 393

Answer:

  $3277.23

Step-by-step explanation:

The future value of the CD with interest at rate r compounded semiannually for t years will be given by ...

  A = P(1 +r/2)^(2t)

where P is the principal value.

For the given rate and time, this is ...

  A = $2000(1 +0.05/2)^(2·10) = $2000(1.025^20) ≈ $3277.23

The value of the CD at maturity will be $3277.23.

6 0
3 years ago
4m-3/4=-9+4m/8 this is my question that i need help with
Bess [88]

Answer:

The answer is -2 5/14 if you're trying to solve for m

Step-by-step explanation:

first you get rid of the fractions by mutiplying both sides by 4.

4(4m-3/4)=(-9+4m/8)4

16m-3=-36+2m      then you put the varible terms on one side and the numbers on one side

14m=-33

then divide -33 by 14

which will give you the fraction -2 5/14 unless you want decimal form which would be around -2.36

5 0
3 years ago
Read 2 more answers
The set of life spans of an appliance is normally distributed with a mean y = 48 months and a standard deviation or
Kamila [148]

Answer:

The set of life spans of an appliance is normally distributed with a mean µ= 48 months and a standard deviation σ= 8 months. ... Thanh finds that his grade on the test has a z-score of -2.5. ... are normally distributed, and the probability that the city gets more than 43.2 inches of rain in a year is given by P(z≥1.5)=0.0668.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Hey i need help pls be honest. WILL GIVE BRAINLIEST!!!!!!!!
Gnoma [55]
12 x 12 = 144
20 x 12 = 240
=384

ANSWER: 384
6 0
3 years ago
Please someone help me...​
Savatey [412]

use a^2-b^2=(a+b)(a-b)

to get (\cos^3A-\sin^3A)(\cos^3A+\sin^3A)

then use a^3+b^3=(a+b)(a^2+b^2-ab)

and a^3-b^3=(a-b)(a^2+b^2+ab)

also, \sin^2\theta+\cos^2\theta=1

to get (\cos A-\sin A)(1+\sin A\cos A)(\cos A+ \sin A)(1-\sin A\cos A)

then again use the first identity In both pairs, i.e.

(\cos A-\sin A)(\cos A+ \sin A) \cdot (1+\sin A\cos A)(1-\sin A\cos A)

to get \cos 2A (1-\sin^2A\cos^2A)

multiply and divide by 4 to get the RHS.

because, \sin(2A)= 2\sin A \cos A

squaring both sides, \sin^2 (2A)=4\sin^2A\cos^2A

3 0
3 years ago
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