B. and D. work. You are trying to figure out how many more cars they painted in the first and second years together than the third year. (5,000+7,213)-8,201=4,012
Answer:
Third sequence (7, 2, 1, -4, -10)
In the first sequence, -4 has to be in front of -10 because it is larger.
In the second sequence, 7 goes in the beginning, with 2 then 1 following, with -4 behind and -10 behind -4.
In the third option, 7 must be in the front, with 2, 1, then -4, then -10 following.
The answer = third sequence.
Hope it helped!
15y + 31 = 61
15y = 61 - 31
15y = 30
y = 30 ÷ 15
<u>y = 2</u>
Answer:
0.970873786408%
Step-by-step explanation:
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