Could you please attach the graph itself because the question is not proper
Answer:
AB{-4,-12}
Step-by-step explanation:
AB=xb-xa
yb-ya
AB{-4-0,-8-4}
AB{-4,-12}
equation of slope is y=ax+b
The perimeter of plot is 200 m. Denote sides of plot with x and y.
![P=2(x+y) \\200=2(x+y) \\100=x+y \\y=100-x](https://tex.z-dn.net/?f=P%3D2%28x%2By%29%0A%5C%5C200%3D2%28x%2By%29%0A%5C%5C100%3Dx%2By%0A%5C%5Cy%3D100-x)
The area of plot is
![A=xy](https://tex.z-dn.net/?f=A%3Dxy)
a)
![A=xy=x(100-x)=100x-x^2](https://tex.z-dn.net/?f=A%3Dxy%3Dx%28100-x%29%3D100x-x%5E2)
b) The area is maximal for A'=0
![A'=(100x-x^2)'=100-2x](https://tex.z-dn.net/?f=A%27%3D%28100x-x%5E2%29%27%3D100-2x)
![100-2x=0 \\100=2x \\x=50 \\ \\y=100-x \\y=100-50 \\y=50](https://tex.z-dn.net/?f=100-2x%3D0%0A%5C%5C100%3D2x%0A%5C%5Cx%3D50%0A%5C%5C%0A%5C%5Cy%3D100-x%0A%5C%5Cy%3D100-50%0A%5C%5Cy%3D50)
The sides of rectangle are x=50 and y=50. Therefore, the area is maximal if the rectangle is a square.
Answer:
Step-by-step explanation:
Here it is