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olganol [36]
3 years ago
6

A dolphin jumps 54 times in a 6 hour

Mathematics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

18  jumps would be  expected in a 2 hour period.        

Step-by-step explanation:

Given : A dolphin jumps 54 times in a 6 hour  period.

To find : At this rate, how many jumps would be  expected in a 2 hour period?​

Solution :

Applying unitary method,

In 6 hour period Dolphin jumps 54 times.

In 1 hour period Dolphin jumps \frac{54}{6} times.

In 1 hour period Dolphin jumps 9 times.

In 2 hour period Dolphin jumps 2\times 9 times.

In 2 hour period Dolphin jumps 18 times.

Therefore, 18  jumps would be  expected in a 2 hour period.

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PLEASE HELP URGENT!! DONT LINK FILES!!! HELP!!
Tomtit [17]

Answer:

Base = 8

Step-by-step explanation:

Area of a triangle can be calculated as:

Area = 0.5 x Base x Height

The values of the area and the height are given in order to find the length.

A= 52 in^2

Height= 13

First we have to find the base or the length. Using the values above we can set up the equation as:

1. 52= (0.5)(13)(b)

2. 52/0.5(13)

3. b=8

Answer: The length of the guitar or the base would be 8 inches.

I hope this helps and for future problems regarding this topic use the formula above!!

Formula: 0.5 x Base x Height

4 0
3 years ago
If 3x + 2 = 4, what is the value of 6x - 4?<br> 2<br> 8<br> 0<br> -2
Sladkaya [172]

Answer:

0

Step-by-step explanation:

3x + 2 = 4

4-2 = 3x

2 = 3x

x = 2/3

2/3 x 6 = 12/3 = 4 - 4 = 0

8 0
3 years ago
The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per
ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that \mu = 2

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

We want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707

P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804

P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902

P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176

1.76% probability that in one hour more than 5 clients arrive

8 0
3 years ago
Read 2 more answers
What is the value of the expression?
fomenos
2/3 would be the value of this expression:)
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3 years ago
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ludmilkaskok [199]

Answer:

238.64 cm

Step-by-step explanation:


4 0
3 years ago
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