Answer:
Step-by-step explanation:
Tangents from the point outside the circle are equal.
x + 7 = 13 +8
x + 7 = 21 {Subtract 7 from both sides}
x = 21 - 7
x = 14
Answer:
<u>Given:</u>
- DC ║ AB
- CM = MB as M is midpoint of BC
i) <u>Since DN and BC are transversals, we have:</u>
- ∠DCM ≅ ∠NBM and
- ∠CDM ≅ ∠BNM as alternate interior angles
<u>As two angles and one side is congruent, the triangles are also congruent:</u>
- ΔDCM ≅ ΔNBM (according to AAC postulate)
So their areas are same.
ii)
<u>The quadrilateral has area of:</u>
- A(ADCB) = A(ADMB) + A(DCM)
<u>And the triangle has area of:</u>
- A(ADN) = A(ADMB) + A(NBM)
Since the areas of triangles DCM and NBM are same, the quadrilateral ADCB has same area as triangle ADN.
The difference between 3/7 and 1/14 is 5/14
Difference can be described as subtracting one number from the other.
The first step is to write out the fractions and subtract 1/14 from 3/7
3/7 - 1/14
= 6-1/14
= 5/14
Hence the difference between 3/7 and 1/14 is 5/14
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The answer is B. Would you like an explanation why?