3 years ago

Write the equation that models the linear relationship

Mathematics

1 answer:

Anettt [7]3 years ago

7 0

Answer:

is it degrees

Step-by-step explanation:

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Equivalent expression for 6 (x+y+z)=

Leya [2.2K]

Answer:

6x + 6y + 6z

Step-by-step explanation:

Distribute the 6 to each value in the parenthesis.

7 0

3 years ago

Read 2 more answers

Seven more than the product of twenty eight and thirty one

Mariulka [41]

The equation should look like this: (28*31)+7= 875

Unless i've completely misunderstood the basis of the equation.

6 0

3 years ago

A demand loan for $8,944.61 with interest at 7.8% compounded semi-annually is repaid after two years, seven months. What is the

disa [49]

Answer:

the correct answer is option D which is $1,954.94

Step-by-step explanation:

loan amount = $8,944.61

interest = 7.8% = 7.8 %/2 = 3.9 %

compounded semi annually = 2 × 12 + 7 = 31 months

time = 31/6 months

$I =P(1+\dfrac{r}{100})^{\frac{31}{6}}-P\\ \\I = 8994.61(1+\dfrac{3.9}{100})^{\frac{31}{6}}-8994.61 \\I =1954.94$

hence, the correct answer is option D which is $1,954.94

7 0

4 years ago

In a certain sequence of all positive terms, {a1, a2, a3, …} each term equals the previous term times a constant factor. If (a1)

andriy [413]

Let $k$ be the constant factor between terms, so that

$a_2=ka_1$

$a_3=ka_2=k^2a_1$

and so on, with

$a_n=ka_{n-1}=\cdots=k^{n-1}a_1$

(notice how the exponent and the subscript add to $n$ )

Then

$a_5=k^4a_1$

so if

$a_1a_5=900$

then

$k^4{a_1}^2=900\implies k^4=\dfrac{900}{{a_1}^2}=\left(\dfrac{30}{a_1}\right)^2\implies k^2=\dfrac{30}{a_1}$

Now,

$a_3=k^2a_1=\dfrac{30a_1}{a_1}=30$

so the third term in the sequence is 30.

7 0

3 years ago

Can someone do this for me pls?

Yuri [45]

1. 13/4
2. 35/4
3. 11/2
4. 52/77
5. 32/3
6. 232/35
7. 32
8. 5/2
9.217/48

4 0

3 years ago