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Law Incorporation [45]
3 years ago
5

A taxicab starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks w

est and 5 blocks north and drops off the passenger. What are the coordinates of the point where the passenger was dropped off?
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0
(x,y)
east is an increase in x
west is a decrease in x
north is an increase in y
south is a decrease in y

so
3 east (x+3)
1 block south (y-1)
6 blocks west (x-6)
5 blocks north (y+5)

so in total, x+3-6 and y-1+5
basically x-3 and y+4
minus 3 from  and add 4 to y
(1,-2)
(1-3,-2+4)
(-2,2) is the dropoff point
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120 pupils went on a feildtrip . 55% of the pupils were girls and the rest were boys. How many boys went on the trip?
wlad13 [49]

Answer:

54 boys went in the trip

Step-by-step explanation:

55% of 120 is 66 and 66 minus 120 is 55

4 0
3 years ago
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What is the solution to the system of equations graphed below?
Mariulka [41]

Answer:

it is (-4,8)

Step-by-step explanation:

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3 years ago
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The lengths of three sides of a quadrilateral are shown below:
julsineya [31]
Answers: 
Part A: 12y² + 10y – 21
Part B: 4y³ + 6y² + 6y – 5 
Part C: See below.

Explanations: 
Part A: 
For this part, you add Sides 1, 2 and 3 together by combining like terms:
Side 1 = 3y² + 2y – 6
Side 2 = 4y² + 3y – 7
Side 3 = 5y² + 5y – 8
3y² + 2y – 6 + 4y² + 3y – 7 + 5y² + 5y – 8
Combine like terms: 
3y² + 4y² + 5y² + 2y + 3y + 5y – 6 – 7 – 8 
12y² + 10y – 21

Part B: 
You have the total perimeter and the sum of three of the sides, so you just need that fourth side value, which we can call d.
P = 4y³ + 18y² + 16y – 26
Sides 1, 2 & 3 = 12y² + 10y – 21 
Create an algebraic expression: 
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d: 
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
– 12y²                                – 12y²
10y – 21 + d = 4y³ + 6y² + 16y – 26 
– 10y                               – 10y
– 21 + d = 4y³ + 6y² + 6y – 26 
+ 21                                + 21 
d = 4y³ + 6y² + 6y – 5 

Part C: 
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y², y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms.
7 0
3 years ago
At an university 70% of the students who attend stay on campus. If 1,380 of the students who attend live off campus, what is the
Alborosie

Answer:

4600

Step-by-step explanation:

We can write a proportion to find the total amount who attend university using the information given. A proportion is two equivalent ratios set equal to each other. Since 70% live on campus, then 30% live off campus and we are told that number is 1,380.

\frac{30}{100}=\frac{1380}{y}

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

30y=100(1380)

30y=138000

y=4600.

There are 4600 students who attend the university.

7 0
3 years ago
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