Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
Answer:
Cosine
Step-by-step explanation:
Cosine = 
Cos 70 = 
0.633 =
0.633 x 8 = x 8
5.064 = x
Answer: 60
Step-by-step explanation: I did the math but sorry if this is wrong
Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic
10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)
Final Answer: 10
Answer:
Dog is 2 years old
Step-by-step explanation:
Let dog's age = d
Let friend's age = f
Your dog is 8 years younger than your friend:
d +8 = f
In 2 years, your friend will be three times as old as your dog:
3(d+2) = (f+2)
3d+6 = f+2
3d = f - 4
(sub in f=d+8 from above)
3d = f - 4
3d = d+8 - 4
2d = 4
d = 2
