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Alenkinab [10]
3 years ago
6

If f(x) = 4x-9, evaluate f(3) I need HELP ASAP!!!!!!!!!!!​

Mathematics
1 answer:
seropon [69]3 years ago
8 0

Answer:

substitute 3 as in x:

4(3)-9

= 12-9

= 3

Hope this helped - have a nice day & be safe

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Write an equation for the vertical line that contains point E(-12, 7). Is anybody able to help?
BigorU [14]

Answer:

x = -12

Step-by-step explanation:

Vertical lines take the form of x = something and horizontal lines take the form of y = something

Why is this? Notice that whenever you make a horizontal line on a graph and select virtually any point that's on that line, all of the points you pick will have the same y value. Try to imagine the same thing with a vertical line, are the results the same?

So the line x = -12 (we got -12 from the coordinate that was given to us on the question prompt) is a vertical line that passes through virtually all possible y values (from positive infinity to negative infinity, or vice-versa) which means that the question prompt having given us the y value was negligible.

Good luck!

5 0
3 years ago
Find the vertex of the graph of the function.
lapo4ka [179]

Answer: The correct options are  (1) (5,10), (2) (3,-3), (3) x = -1, (4) y=(x+2)^2+3, (5) 21s and (6) 0, -1, and 5.

Explanation:

Te standard form of the parabola is,

f(x)=a(x-h)^2+k        .....(1)

Where,  (h,k) is the vertex of the parabola.

(1)

The given equation is,

f(x)=(x-5)^2+10

Comparing this equation with equation (1),we get,

h=5 and k=10

Therefore, the vertex of the graph is (5,10) and the fourth option is correct.

(2)

The given equation is,

f(x)=3x^2-18x+24

f(x)=3(x^2-6x)+24

To make perfect square add (\frac{b}{2a})^2, i.e., 9. Since there is factor 3 outside the parentheses, so subtract three times of 9.

f(x)=3(x^2-6x+9)+24-3\times 9

f(x)=3(x-3)^2-3

Comparing this equation with equation (1),we get,

h=3 and k=-3

Therefore, the vertex of the graph is (3,-3) and the fourth option is correct.

(3)

The given equation is

f(x)=4x^2+8x+7

f(x)=4(x^2+2x)+7

To make perfect square add (\frac{b}{2a})^2, i.e., 1. Since there is factor 4 outside the parentheses, so subtract three times of 1.

f(x)=4(x^2+2x+1)+7-4

f(x)=4(x+1)^2+3

Comparing this equation with equation (1),we get,

h=-1 and k=3

The vertex of the equation is (-1,3) so the axis is x=-1 and the correct option is 2.

(4)

The given equation is,

y=x^2+4x+7

To make perfect square add (\frac{b}{2a})^2, i.e., 2^2.

f(x)=x^2+4x+4+7-4

f(x)=x^2+4x+4+7-4

f(x)=(x+2)^2+3

Therefore, the correct option is  4.

(5)

The given equation is,

h=-16t^2+672t

It can be written as,

h=-16(t^2-42t)

It is a downward parabola. so the maximum height of the function is on its vertex.

The x coordinate of the vertex is,

x=\frac{b}{2a}

x=\frac{42}{2}

x=21

Therefore,  after 21 seconds the projectile reach its maximum height and the correct option is first.

(6)

The given equation is,

f(x)=3x^3-12x^2-15x

f(x)=3x(x^2-4x-5)

Use factoring method to find the factors of the equation.

f(x)=3x(x^2-5x+x-5)

f(x)=3x(x(x-5)+1(x-5))

f(x)=3x(x-5)(x+1)

Equate each factor equal to 0.

x=0,-1,5

Therefore, the zeros of the given equation is 0, -1, 5 and the correct option is 2.

3 0
3 years ago
In circle D, if the measure of arc Gec is 230 , what is the measure of minor arc GFC
BabaBlast [244]

Answer:

The measure of minor arc GFC is 130\°

Step-by-step explanation:

we know that

In a circle the sum of the major arc plus the minor arc is equal to 360 degrees

see the attached figure to better understand the problem

Let

x------> the major arc GEC

y-----> the minor arc GFC

so

x+y=360\°

we have

x=230\°

substitute in the equation and solve for y

230\°+y=360\°

y=360\°-230\°=130\°

8 0
3 years ago
The endpoints of a line segment graphed on the coordinate system are (−7, 3) and (2, 5). What is the range of the graph?
Eduardwww [97]
I think the answer would be C
4 0
3 years ago
5+-7+3+-6=-5 what is the work
spayn [35]
5+(-7)+3+(-6)=-5
Answer is zero
6 0
3 years ago
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