Your 2 points are (1,2) and (3,-1)

m(slope) = y2 - y1 / x2 - x1

m = -1 - 2 / 3 - 1

m = -3 / 2 , -1.5

<span>6.2x+1.2=8.9

</span>estimate<span>

6x + 1 = 9

6x = 8

x = 8/6

x = 1.33

answer

x = 1.33</span>

y = 6 it a horizontal line. The line parallel to horizontal line is horizontal line with the equation y = a.

The line passing through the point (3, 4) → y = 4.

Therefore your answer is : **y = 4.**

The **coordinates** of **point P** is the location of **point P **in the **coordinate plane**

The **coordinates** of point of P is (a + c, b)

<h3>How to determine the coordinate of P</h3>

From the complete question (see attachment), **point P **and the **coordinate **(a,b) are on the same **horizontal line**.

This means that the **y-coordinate **of **point P **is b

To determine the **x-coordinate **of **point P, **we make use of the following equation

x = a+ c

This is so because, the **horizontal line **from **coordinate **(a,b) to **line P **has the same length as line 0c.

So, the **coordinates** of point of P is:

P = (a + c, b)

Hence, the **coordinates** of point of P is (a + c, b)

Read more about **coordinates** at:

brainly.com/question/7243416

Answer:

The value of x^3 + 1/x^3 is 47/x + 1/x^3 - 1/x^5

Step-by-step explanation:

x^4 + 1/x^4 = 47

x^4 = 47 - 1/x^4

x^3 + 1/x^3 = 1/x(x^4 + 1/x^2)

x^4 = 47 - 1/x^4

x^3 + 1/x^3 = 1/x(47 - 1/x^4 + 1/x^2) = 47/x - 1/x^5 + 1/x^3 = 47/x + 1/x^3 - 1/x^5