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SSSSS [86.1K]
3 years ago
10

Rewrite 11/21 and 5/9 so that they have common denominator

Mathematics
1 answer:
Effectus [21]3 years ago
3 0
11/21 * 3/3 = 33/63
5/9 * 7/7 = 35/63
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What is 8 +2+8+8+8+8+7+9+9+9+9+9+9+0+9+9+909090+9+9-9+9
Angelina_Jolie [31]

Answer:

its 909,229 you just add the numbers

6 0
3 years ago
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Can someone please help me?!!!
Natasha2012 [34]
SOLUTION:

Alternate angles on paralell lines.

This means:

2x + 10° = 62°

2x = 62 - 10

2x = 52

x = 52 / 2

x = 26


Sorry, I tried to answer this but I only got this far. I'm not exactly sure about the ? < x < ? as my answer didn't give an answer with > or <. Unless there are different numbers which you can put for your answer based on what ( x ) is equal to, I'm not sure what the answer is & I doubt that they would allow for multiple answers.
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3 years ago
Please help me somebody
miskamm [114]
Answer c: 1/4 divided by 2
8 0
3 years ago
2^{51} mod 22 in words, two to the power of fifty-one mod twenty-two
andreyandreev [35.5K]

Since 2⁵ = 32, and

2⁵ ≡ 32 ≡ 10 (mod 22),

we have

2⁵¹ ≡ 2 • 2⁵⁰ ≡ 2 • (2⁵)¹⁰ ≡ 2 • 10¹⁰ (mod 22)

Now consider 10¹⁰ (mod 22):

10 = 2 • 5

10¹⁰ ≡ 2¹⁰ • 5¹⁰ ≡ (2⁵)² • 5¹⁰ ≡ 10² • 5¹⁰ ≡ 2² • 5¹² (mod 22)

so that

2⁵¹ ≡ 2³ • 5¹² (mod 22)

Now consider 5¹² (mod 22):

5 and 22 are coprime, and ɸ(22) = 10 (where ɸ(<em>n</em>) is the Euler totient function). By Euler's theorem,

5¹² ≡ 5² • 5¹⁰ ≡ 5² • 1 ≡ 25 ≡ 3 (mod 22)

and so

2⁵¹ ≡ 2³ • 3 ≡ 24 ≡ 2 (mod 22)

Another, more tedious method: Start with smaller powers of 2 and look for a pattern.

2 ≡ 2 (mod 22)

2² ≡ 4 (mod 22)

2³ ≡ 8 (mod 22)

2⁴ ≡ 16 (mod 22)

2⁵ ≡ 32 ≡ 10 (mod 22)

2⁶ ≡ 2 • 32 ≡ 2 • 10 ≡ 20 (mod 22)

2⁷ ≡ 2 • 20 ≡ 40 ≡ 18 (mod 22)

2⁸ ≡ 2 • 18 ≡ 36 ≡ 14 (mod 22)

2⁹ ≡ 2 • 14 ≡ 28 ≡ 6 (mod 22)

2¹⁰ ≡ 2 • 6 ≡ 12 (mod 22)

2¹¹ ≡ 2 • 12 ≡ 24 ≡ 2 (mod 22)

2¹² ≡ 2 • 2 ≡ 4 (mod 22)

and so on, with a cyclic pattern of length 10. That is, 2^{10k+1}\equiv2\pmod{22} for any integer <em>k</em> ≥ 0. So 2⁵¹ ≡ 2 (mod 22).

3 0
3 years ago
Paul, Linda, and Aaron make handmade cards. Paul can make 1 card for every 3 cards Linda makes. Linda can make 3 cards for every
patriot [66]

Answer:

Linda makes 3 more cards than Paul.

Step-by-step explanation:

Let's express the affirmations into equations:

Paul (P) can make 1 card for every 3 cards Linda (L) makes:

\frac{P}{L} = \frac{1}{3}

3P = 1L            (1)

Linda can make 3 cards for every 2 cards that Aaron (A) makes:

\frac{L}{A} = \frac{3}{2}  

2L = 3A          (2)        

During a week, Aaron makes 72 cards, hence the number of cards of Linda and Paul can be calculated as follows:

From equation (2):

L = \frac{3}{2}A = \frac{3}{2}72 = 108

Now, from equation (1):

P = \frac{1}{3}L = \frac{1}{3}108 = 36

Finally, the number of cards that Linda makes more than Paul is:

\frac{L}{P} = \frac{108}{36} = 3

Therefore, Linda makes 3 more cards than Paul.

I hope it helps you!    

5 0
3 years ago
Read 2 more answers
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