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cluponka [151]
3 years ago
13

What is the extraneous root of this problem?

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0

Answer:

a: -6

Step-by-step explanation:

\sqrt{5(-6)+6} =\sqrt{-24} = -6\\

This equation is not correct, therefore A is not a root and is extraneous

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