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sertanlavr [38]
3 years ago
13

What is (6^3 - 9 - 1)​

Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0
That answer would be 206
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4 is the mode for this question

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Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
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Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

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Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
4 years ago
Determine the center and radius of the following circle equation:<br> x^2+y^2+12x-10y+12=0
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Center: ( -6,5) Radius: 7

Step-by-step explanation:

I hope this helps!

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The answer to it is (-5,13),(1,1),(2,-1)
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