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Lady bird [3.3K]

3 years ago

14

Write the standard form of the equation of the line passing through the point (1, 5) and perpendicular to the line 4x - 7y = – 2

8.

1 answer:

aleksley [76]3 years ago

4 0

Answer:

you put two of the equations together and then the last one there you just automatically added on

Step-by-step explanation:

4x-7y=-28

25xy

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Determine which ordered pairs are part of the solutions set for the inequality.(Hint - There may be more than 1 correct answer)"

Alisiya [41]

These ordered pairs<span> are in the </span>solution set<span> of the equation </span>x<span> > </span>y. ... (2<span>, </span>0<span>). </span>3(2<span>) + </span>2(0<span>) ≤ 6. 6 + </span>0<span> ≤ 6. 6 ≤ 6. (</span>4, −1<span>). </span>3(4<span>) + </span>2(−1) ≤ 6. 12 + (−2<span>) ≤ 6 ... </span>3<span>). </span>

6 0

4 years ago

PLEEEEEEEAAAAAAASSSSSSSSSSEEEEEEEEEEE help me!!!!!!!!!!

defon

Answer:

$\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }$

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

we can write that, (the different answers provide good clues :-) )

$x^2+5x-84=(x-7)(x+12)$

and

$x^2+23x-210=(x-7)(x+30)$

so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write

$\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}$

hope this helps

7 0

3 years ago

Solve for x: 2-3(2x-1)=-6x+5

horrorfan [7]

Answer:

x=-1

Step-by-step explanation:

1.) 2-3(2x-1)=-6x+5

2.) -1(-2x-1)=-6+5

3.) (2x+1)=-6+5

4.) (2x+1)=-1

5.) 2x=-2

6.) x=-1

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3 years ago

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wlad13 [49]

It’s c lease mark me brainliest

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3 years ago

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spayn [35]

Answer:

36

Step-by-step explanation trust me perimeter is all the sides added up

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3 years ago

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