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3 years ago

What is the 72nd term of arithmetic sequence-27,-11,5

Mathematics

2 answers:

otez555 [7]3 years ago

7 0

Answer:

1109

Step-by-step explanation:

you can subtract the terms to see the difference between them

-11-(-27)=16

The sequence is increasing by 16

you can plug that 16 in the formula for d

a_n=a_1+(n-1)d

a_n=a_1+(n-1)16

n represents the term you want to find in this case the 72nd

a sub 1 is the first term of the sequence in this case -27

a_72=-27+(72-1)16

a_72=-27+(71)16

a_72=-27+1136

a_72=1109

irinina [24]3 years ago

6 0

Answer:

1109.

Step-by-step explanation:

The common difference is -11 - (-27) = 16 (also 5 - -11 = -16)

72nd term = a1 + d(n -1)

= -27 + 16(71)

= 1109.

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A cell phone costs $448, a battery charger costs $14, and batteries cost $7. What is the sales tax and total price for purc

Leokris [45]

Add all 3 costs to find the total cost before taxes.

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4 years ago

What is the value in cents of 10 quarters and 2 dimes

BaLLatris [955]

Answer:

250+20 = 270 cents or $2.70

Step-by-step explanation:

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5 0

3 years ago

Solve x2 + 6x + 7 = 0. (2 points)

Alexandra [31]

Option C: $$x=-3 \pm\sqrt{2}$

Solution:

Given equation is $x^{2}+6 x+7=0$ .

This is a quadratic equation.

Here a = 1, b = 6, c = 7

To solve the given equation by quadratic formula,

$$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Substitute the given values in the quadratic formula, we get

$$x=\frac{-6 \pm \sqrt{6^{2}-4 (1) (7)}}{2 (1)}$

$$x=\frac{-6 \pm \sqrt{36-28}}{2 }$

$$x=\frac{-6 \pm \sqrt{8}}{2 }$

$$x=\frac{-6 \pm2 \sqrt{2}}{2 }$

$$x=\frac{2(-3 \pm\sqrt{2})}{2 }$

2 in the numerator and denominator are cancelled.

$$x=-3 \pm\sqrt{2}$

Option C is the correct answer.

8 0

3 years ago

Find the measure of angle A

Brut [27]

Answer:

-7

Step-by-step explanation:

The sum of all angles in a triangle will be equal to 180.
So we add x+46+x+71+77=180*
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5 0

3 years ago

The sum of the roots of 3x 2 + 11x - 4 = 0 is -11/3 -4/3 11/3 4/3

givi [52]

Answer:

The correct option is 1.

Step-by-step explanation:

If a quadratic equation is defined as

$ax^2+bx+c=0$ .... (1)

Then the sum of the roots is -b/a and the product of roots is c/a.

The given equation is

$3x^2+11x-4=0$ ... (2)

From (1) and (2) we get a=3, b=11 and c=-4.

The sum of roots is

$\frac{-b}{a}=-\frac{11}{3}$

The sum of roots is $-\frac{11}{3}$ .

Therefore the correct option is 1.

5 0

4 years ago