Y = 3x + 3
y = x - 1
As you can see, both equations are set to equal y. This means the right sides of each equation are equal, since y is isolated in both equations. So to solve this particular system of equations for x, set the right sides of both equations equal to each other. After you've done that, you can proceed to solve the equation algebraically for the variable, x.
3x + 3 = x - 1
2x + 3 = -1
2x = -4
x = -2
Negative two is the x-value. To find the y-value, substitute -2 for x into either equation and solve algebraically for y.
y = x - 1
y = -2 - 1
y = -3
The final step is to check all work by plugging both x- and y-values back into both equations.
y = 3x + 3
-3 = 3(-2) + 3
-3 = -6 + 3
-3 = -3 -- This is true
y = x - 1
-3 = -2 - 1
-3 = -3 -- This is true.
Answer:
(-2, -3)
Remember
(x^n)^m=x^(mn)
(x^4)^2=x^(4*2)=x^8
Area of a triangle is = 0.5bh
if the height (h) is 4 less than base (b) then h = b - 4
48 = 0.5(b)(b - 4)
48/0.5 = b² - 4b
96 = b² - 4b
b² - 4b - 96 = 0
(b + 8)(b - 12) = 0
b must be either -8 or 12
since a distance can't be negative that means
the base is 12
Since the angle 225° is in the third quadrant, the reference
angle formula is Ar=Ac-180°. Ar = 225° − 180°
Ar=225°-180°
The reference angle is Ar=45°
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Answer:
There is a 50.18% probability that they are of the same gender.
Step-by-step explanation:
We have these following percentages:
53% of the students are males.
47% of the students are females.
If two students from this college are selected at random, what is the probability that they are of the same gender?
The probability that each is male is 53%. So the probability of both being males is
The probability that each is female is 47%. So the probability of both being females is
The probabilty that both are the same gender is:
There is a 50.18% probability that they are of the same gender.
