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vichka [17]
3 years ago
6

Does the line y=x intersect the parabola y=-x².If so, how many times and where? Draw graphs on the same set of axes.

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

Yes, the line intersects the parabola two times at the points (0,0) and (-1,-1)

Step-by-step explanation:

Hi there!

We have the following system of equations:

y = x

y = -x²

If the curves intersect, then there is at least a pair (x,y) that satisfies both equations. That will only happen for those values of x for which:

-x² = x

The only two values that satisfy that equality are 0 and -1.

When x = 0, y is also 0 for both functions. In the same way, when x = -1 y is also -1 for both functions. Then, the curves will intersect at the points (0, 0) and (-1, -1).

Please, see the attached graphic for a better understandign of the problem.

Have a nice day!

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Answer:

The answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

Step-by-step explanation:

\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}

Solve the L.H.S part:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]

After calculating the L.H.S part compare the value with R.H.S:

\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\

\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\

In equation (i) multiply by 3 and subtract by equation (iii):

\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to  c= - \frac{1}{2}

put the value of c in equation (i):

\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\

In equation (ii) multiply by 3 then subtract by equation (iv):

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put the value of d in equation (iv):

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