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alexandr1967 [171]
3 years ago
12

A teacher reaches into a bag of game pleces containing 5 black pleces, 3 purple pleces, 1 orange plece, and 6 green pleces, He d

raws 2 pleces, setting aside the first
plece before drawing the second. What is the probability that at least one of the drawn pleces ls purple?
Mathematics
2 answers:
ElenaW [278]3 years ago
6 0

Answer:

3/15

Step-by-step explanation:

inna [77]3 years ago
3 0
The probability of choosing a purple piece is 3/15, choosing an orange piece will be 1/15, that of black pieces is 5/15 and that of choosing a green piece is 6/15.
This would be PP + PW+ PG + PB +WP +GP + BP
= (3/15 × 2/14) + (3/15×1/14)+(3/15×6/14) +(3/15+5/14)+(1/15×3/14) + (6/15× 3/14) + (5/15 × 3/14)
= 6/210 +3/210 +18/210+15/210+3/210 +18/210+ 15/210
= 78/210
= 13/35
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Answer: Roughly 111.97

Step-by-step explanation:

1. 39 divided by 3 is 13.  

2. 4367 divided by 3 is not evenly distributed. Rounding, it would work out to be roughly 1455.66 

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4. To check your work, multiply 111.97 times 13 and you should get somewhere around 1455.66 which is (4367 divided by 3).

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