Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean total cholesterol level of all males.
Number of sample, n = 355
Mean, u = 185 mg
Standard deviation, s = 16
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
185 +/- 1.96 × 16/√355
= 185 +/- 1.96 × 0.849
= 185 +/- 1.66404
The lower end of the confidence interval is 185 - 1.66404 =183.336
The upper end of the confidence interval is 185 + 1.66404 = 186.66
Therefore, with 95% confidence interval, the mean total cholesterol level of all males is between 183.336 mg and 186.66 mg
1st data set:
Minimum: 34
1st quartile: 35
Median: 36
3rd quartile: 37
Maximum: 38
Second data set:
Minimum: 20
1st quartile: 23
Median: 25
3rd quartile: 38
Maximum: 65
Graph
it based on the values of the 1st and 3rd quartile. If they are both
the same number away from the mean then they are symmetrical. Otherwise
they are not. In this case, the first one is similar and the second one
is not.
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I am pretty good at any math and I love a good challenge. What is your question because I'd be glad to help!!!
C) 30 * IQR is the box. So the highest point on the box is 95 and the lowest is 65, which makes the difference 30. I hope this helped!!
