<h3>
<u>Explanation</u><u>:</u></h3>
Consider ABCD is a rhombus
We know that
All sides are equal in rhombus
=> AB=BC=CD=DA
and AC and BD are digonals
Given that
Diagonal and the side of the rhombus are equal.
=> AB = BC = CD = DA = AC
Diagonal AC divides the rhombus into two triangles .
They are ∆ BAC and ∆ DAC
In triangle BAC
BA=BC=AC,(Given)
=> < BAC=<ABC= < ACB =60°………(1)
Similarly in ∆DAC ,
DA=DC=AC
=><DAC=<ACD=<ADC=60°……….(2)
From (1) and (2)
<A=<BAC+< DAC=60°+60°=120°
and
< B= < ABC = 60°.
and
<C=<ACB+<ACD=60°+60°=120°
and
< D =<ADC=60°
Therefore, <A = 120° , <B = 60° ,<C = 120° ,<D = 60°
<u>Answer:-</u>
The measures of the all angles in the rhombus are 120° , 60° ,120° and 60°
<u>Used formulae:-</u>
all sides in a rhombus are equal
#17) 8 cubic feet.
#19) 5 miles.
g(x) is a result of a vertical shift (aka translation) of the graph f(x) down by 3 units.
Answer: 1. x^2-5x+4
2. x^2-7x+6
3. x^3-7x^2+11x-5
4. x-5
Step-by-step explanation:
1. x^2-6x+5+x-1=
x^2-6x+x+5-1=x^2-5x+4
2. x^2-6x+5-(x-1)=
x^2-6x+5-x+1=
x^2-6x-x+5+1=x^2-7x+6
3. (x^2-6x+5) * (x-1)=
x(x^2-6x+5)-1(x^2-6x+5)=
x^3-6x^2+5x-x^2+6x-5=
x^3-6x^2-x^2+5x+6x-5=x^3-7x^2+11x-5
4. (x^2-6x+5)/(x-1)=
(x^2-x-5x+5)/(x-1)=
(x(x-1)-5(x-1))/(x-1)=
(x-5)(x-1)/(x-1)=x-5
Well it depends...... (.5= 1/2)
